Deformation theory
Let be a nonsingular projective variety over
, and let
be a one-dimensional closed subscheme. We have
, the ideal sheaf of
, and we assume that
is a local complete intersection, or what is equivalent,
is a locally free sheaf of
-modules of rank
. For example, this holds if
is a nodal curve.
Definition.
The normal bundle of the curve in
is
We have that
Example.
In the case where
, with
is a smooth genus
curve, and
having at worst simple branchings, then there are no obstructions to deformation and
A map of moduli spaces
Let
be a nonconstant morphism with
a nonsingular projective variety over
, and let
be a closed subscheme which is a smooth curve of genus
, such that the ramification of
is simple. In a (formal) neighborhood of
, the spaces
and the
are the same. The map
Corollary. If is contained in the smooth locus of
, and
is ``sufficiently positive'', then the morphism
One argues that the Hilbert scheme is smooth at the point
since one can twist by a small number of points and keep that the
vanishes. In particular, the corollary implies that the morphism is surjective.
We are now ready to prove:
Theorem. [G, Harris, Starr]
If
,
, then any rationally connected variety over
for
a curve has a rational point.
Step . Take a general complete intersection
; it will be smooth, irreducible, of say genus
and degree
. The condition
implies that
is in the smooth locus and
(by Bertini) has at worst simple branching.
Step . Choose a large integer
and choose general points
, and rational curves
such that:
Now let
. The basic property is that
. Moreover,
with colength
and assumption (iv) gives that this is ``general''. This gives that the sheaf
on
is sufficiently positive.
Now deform this curve to a simply branched curve, and this gives the result; conclude by the corollary.
Multiple fibres
We must deal with the case when fails. Suppose we have a family of varieties
with fibres at
irreducible of multiplicity
. Since the curve must intersect these fibres transversally, this must be preserved in any deformation, meaning that the ramification index at
will be divisible by
.
In this case, the problem is:
cannot dominate. Instead, we consider consider the subset
consisting of stable maps
,
of genus
,
of degree
, such that all ramification indices above
are equal to
.
Now we have the additional problems: Which reducible curves are in
? And perhaps
is too small? To resolve both problems, enlarge the genus
(but not
) by adding loops to
: join two points with a good rational curve. This allows you to break off a component even in this case.
Conclusion
This is work with Jason Starr. What will guarantee the existence of a rational point on a variety over a function field in two variables? Is there a geometric condition which would be like rational connectedness in this case? This is too much to hope for, there are many surfaces with a nontrivial Brauer-Severi variety
. Maybe there are geometric restrictions on the fibres
such that one obtains a rational section.
A good guess for this condition: demand that certain moduli spaces of rational curves on the fibers are themselves rationally connected. For example, Starr and Harris proved that for hypersurfaces of degree
in
with
, the moduli spaces of rational curves of fixed degree on
are themselves rationally connected.
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main index
for Rational and integral points on higher dimensional varieties.